Chemistry High School
Answers
Answer 1
The normal human body temperature of 98.6°F is equivalent to 37°C.
The normal human body temperature of 98.6°F is also equivalent to 310.15 K.
What is the normal temperature of human body in celsius?
To convert a temperature from Fahrenheit to Celsius, you can use the formula:
°C = (°F - 32) x 5/9
where °F is the temperature in Fahrenheit and °C is the temperature in Celsius.
To apply this formula to the problem given, we can substitute 98.6°F for °F:
°C = (98.6 - 32) x 5/9
°C = 66.6 x 5/9
°C = 37
Therefore, the normal human body temperature of 98.6°F is equivalent to 37°C.
To convert a temperature from Celsius to Kelvin, you can use the formula:
K = °C + 273.15
where K is the temperature in Kelvin and °C is the temperature in Celsius.
To apply this formula to the problem given, we can substitute 37°C for °C:
K = 37 + 273.15
K = 310.15
Therefore, the normal human body temperature of 98.6°F is also equivalent to 310.15 K.
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Related Questions
in the present of the protein lactose bacteria cells produce enzymes that break down lactose when lactose is not present how do bacterial cells stop the production of enzymes
Answers
In the absence of lactose, bacterial cells stop the production of enzymes by using a regulatory mechanism called the lac operon.
The lac operon is a set of genes that control the production of enzymes involved in the breakdown of lactose in bacteria like Escherichia coli.
It consists of three structural genes (lacZ, lacY, and lacA) and two regulatory elements (the promoter and the operator). When lactose is not present, a protein called the lac repressor binds to the operator region, which blocks RNA polymerase from binding to the promoter and initiating the transcription of the structural genes.
As a result, the enzymes (such as β-galactosidase) required for lactose breakdown are not produced.
Bacterial cells regulate the production of enzymes needed for lactose metabolism through the lac operon. In the absence of lactose, the lac repressor prevents the expression of the necessary genes, stopping enzyme production.
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Based on the equation below,how many grams of nitrogen gas, N2 will be produced from the decomposition of 23.0 grams of sodium azide, NaN3?
NaN3 → Na + N2
Answers
Based on the given equation, 4.96 grams of nitrogen gas, N2, will be produced from the decomposition of 23.0 grams of sodium azide, NaN3.
The number of grams of nitrogen gas, N2, that will be produced from the decomposition of 23.0 grams of sodium azide, NaN3, we need to use stoichiometry.
From the balanced equation, we can see that 2 moles of NaN3 will produce 1 mole of N2. To calculate the number of moles of NaN3 in 23.0 grams, we need to divide the mass by the molar mass:
23.0 g NaN3 / 65.01 g/mol NaN3 = 0.353 mol NaN3
Now that we know the number of moles of NaN3, we can use the stoichiometric ratio to calculate the number of moles of N2: 0.353 mol NaN3 × (1 mol N2 / 2 mol NaN3) = 0.177 mol N2
Finally, we can calculate the mass of N2 produced by multiplying the number of moles by the molar mass:
0.177 mol N2 × 28.02 g/mol N2 = 4.96 g N2
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are molecules without line pairs on CA always non polar
Answers
Molecules without line pairs on CA are not always non polar and depends upon molecular geometry and the bond dipoles.
Hi! Molecules without line pairs on the central atom (CA) are not always non-polar.
Polarity in a molecule is determined by the difference in electronegativity between the atoms and the molecular geometry. While having no lone pairs on the central atom may lead to a symmetrical molecular shape, it's essential to consider the bond dipoles as well. If the bond dipoles do not cancel out, the molecule can still be polar, even without lone pairs on the central atom.
So, it's important to evaluate both the molecular geometry and the bond dipoles to determine if a molecule without lone pairs on the central atom is non-polar.
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An alcohol consists of an "R" group combined with the:
A) double bonded oxygen
B)hydroxyl radical
C) hydroxide ion
Answers
The correct answer to the question is B) hydroxyl radical.
An alcohol is a type of organic compound that contains a hydroxyl group (-OH) attached to a carbon atom in an R group. This hydroxyl group is bonded covalently to the carbon atom, giving rise to a polar molecule. The hydroxyl group is responsible for the properties of alcohols, such as their solubility in water and their ability to form hydrogen bonds.
The hydroxyl radical (-OH) is a highly reactive molecule that contains an unpaired electron. In alcohols, the hydroxyl group is attached to an R group, which can be a simple alkyl chain or a more complex molecule. The presence of the hydroxyl group in alcohols makes them useful in a variety of applications, such as solvents, fuels, and pharmaceuticals.
Overall, alcohols are important organic compounds that are widely used in industry and everyday life. Understanding their structure and properties is essential for many applications, including chemical synthesis, biochemistry, and environmental science. By knowing the different types of alcohols and their characteristics, we can use them more effectively and responsibly.
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pressures
of the three gases in the tank are 60.0 atm of O2, 2.0 atm of N2, and 17.0 atm of He,
how many moles of each gas are present inside of the tank?
7. If a steel container holds 3.00 atm of hydrogen gas and 3.50 atm of helium gas, and the
tatal nressure is 7.00 atm.. what is the partial pressure of Oxygen gas of the gases?
Answers
The partial pressure of oxygen gas (O₂) in the mixture is 0.50 atm.
Ideal Gas Law: PV = nRT, where P is pressure, V is volume, n is the number of moles, R is the gas constant, and T is the temperature. Since the volume (V) and temperature (T) are constant, we can rearrange the equation to find n (moles) for each gas:
n = PV/RT
For your second question, we are given the total pressure (7.00 atm) and partial pressures of hydrogen gas (3.00 atm) and helium gas (3.50 atm). To find the partial pressure of oxygen gas, we can use the following equation:
Total pressure = P_H₂ + P_He + P_O₂
7.00 atm = 3.00 atm (H₂) + 3.50 atm (He) + P_O₂
Now we just need to solve for P_O₂:
7.00 atm - 3.00 atm - 3.50 atm = P_O₂
0.50 atm = P_O₂
So, the partial pressure of oxygen gas (O₂) in the mixture is 0.50 atm.
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A 510 kg sailboat is being pulled with a rope by a truck with a force of 965 N causing the boat to accelerate at 1.8 m/s2 to the left.
Answers
There's a small discrepancy between the applied force (965 N) and the calculated force (918 N), which might be due to rounding or measurement errors.
To calculate the force required to accelerate the sailboat, we can use the formula F = m*a, where F is the force, m is the mass, and a is the acceleration.
So, F = (510 kg)*(1.8 m/s^2) = 918 N.
However, in this scenario, the truck is pulling the sailboat with a force of 965 N, which is greater than the force required to accelerate the boat. This means that the boat will not only accelerate to the left, but it will also experience a net force to the right.
To find the magnitude of this net force, we can use the formula F_net = F_applied - F_friction, where F_applied is the force applied by the truck and F_friction is the force of friction acting in the opposite direction.
Since the sailboat is being pulled on a flat surface, we can assume that the force of friction is negligible. Therefore, F_net = F_applied = 965 N.
Now, to find the time it takes for the sailboat to reach a velocity of 150 m/s to the left, we can use the formula v = a*t, where v is the velocity, a is the acceleration, and t is the time.
Rearranging the formula, we get t = v/a. Substituting in the given values, we get t = (150 m/s) / (1.8 m/s^2) = 83.3 seconds.
So, the long answer to your question is that the sailboat will experience a net force of 965 N to the right, and it will take 83.3 seconds to reach a velocity of 150 m/s to the left.
a 510 kg sailboat is being pulled by a truck with a force of 965 N, which results in an acceleration of 1.8 m/s² to the left. Using Newton's second law (F = m * a), we can check if the force applied by the truck is consistent with the sailboat's mass and acceleration:
F = m * a
965 N = 510 kg * 1.8 m/s²
Solving for the force, we get:
965 N = 918 N
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A gas in a 5.00 L container at 17.5 C is stretched out to 7.50 l, what is the temperature
Answers
The temperature of the gas after it has been stretched out to 7.50 L is 11.7 C.
This can be determined using the combined gas law equation, which states that P1V1/T1 = P2V2/T2. Since the pressure of the gas is constant, we can simplify the equation to V1/T1 = V2/T2.
Substituting the given values, we have:
(5.00 L)/(17.5 + 273.15 K) = (7.50 L)/(T2 + 273.15 K)
Solving for T2, we get:
T2 = (7.50 L)/(5.00 L) x (17.5 + 273.15 K) - 273.15 K = 284.8 K
Converting this to Celsius, we have:
T2 = 284.8 K - 273.15 K = 11.7 C
Therefore, the temperature of the gas after it has been stretched out to 7.50 L is 11.7 C.
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Which unit can be used to express the rate of a reaction?
ОА.
mL/s
OB. ml/g
O c. g/mL
OD. mL/mol
O E
s/mL
Answers
The unit that is commonly used to express the rate of a chemical reaction is mol/L/s or M/s. This unit represents the change in concentration of reactants or products per unit time, usually measured in seconds.
Other units that can also be used to express the rate of a reaction include mL/s or L/s, which represents the volume of a solution that reacts per unit time, and g/s or mg/s, which represents the mass of a substance that is consumed or produced per unit time. It is important to note that the units used to express the rate of a reaction may vary depending on the type of reaction and the specific conditions under which it occurs.
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the enclosed cabin of a submarine had a volume of 2.4x10^5 liters, a temperature of 312K, and a pressure of 116kPa. As people in the cabin breathe, carbon dioxide gas, CO2(g), can build up to unsafe levels. Air in the cabin becomes unsafe to breathe when the mass of CO2(g) in this cabin exceeds 2156 grams
Part 1: convert the original air pressure in the cabin of the submarine to atmospheres
Part 2: Determine the number of moles of CO2(g) in the submarine cabin at which the air becomes unsafe to breathe. The gram-formula mass of CO2 is 44.0 g/mol.
Part 3: State what happens to the average kinetic energy of the gas molecules if the cabin temperature decreases.
Answers
1: To convert the original air pressure in the cabin of the submarine to atmospheres, use the conversion factor 1 atm = 101.325 kPa. 116 kPa * (1 atm / 101.325 kPa) ≈ 1.145 atm
So, the air pressure in the cabin is approximately 1.145 atmospheres.
Part 2: To determine the number of moles of CO₂(g) at which the air becomes unsafe to breathe, use the mass of CO₂ and its gram-formula mass: 2156 g CO₂ * (1 mol CO₂ / 44.0 g CO₂) ≈ 48.9 mol CO₂
So, the air becomes unsafe to breathe when there are approximately 48.9 moles of CO₂ in the cabin.
Part 3: If the cabin temperature decreases, the average kinetic energy of the gas molecules decreases as well. This is because the average kinetic energy is directly proportional to the temperature in kelvins.
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what atomic or hybrid orbitals make up the sigma bond between c1 and c2 in acetic acid ch3cooh?
What is the approximate H-C1-C2 bond angle?
Answers
The sigma bond between C1 and C2 in acetic acid is formed by the overlap of sp3 hybrid orbitals on both carbon atoms.
The sigma bond between C1 and C2 in acetic acid (CH3COOH) is made up of three hybrid orbitals - two sp3 hybrid orbitals from each carbon atom and one sp2 hybrid orbital from the oxygen atom. The hybridization of the carbon atoms in acetic acid is sp3, meaning that each carbon atom has four hybrid orbitals that are involved in bonding. Two of these orbitals are used to form sigma bonds with the two hydrogen atoms, one is used to form the sigma bond with the oxygen atom, and the fourth orbital is used to form the sigma bond with the other carbon atom. The oxygen atom also has a sp2 hybrid orbital that is used to form the sigma bond with the carbon atom.
The approximate H-C1-C2 bond angle in acetic acid is approximately 112 degrees. This bond angle is slightly smaller than the ideal tetrahedral angle of 109.5 degrees due to the repulsion between the lone pair of electrons on the oxygen atom and the bonding pairs of electrons on the adjacent carbon atoms. The sp3 hybridization consists of three p orbitals and one s orbital, resulting in four hybrid orbitals that create a tetrahedral arrangement around each carbon atom. The approximate H-C1-C2 bond angle in acetic acid is close to 109.5 degrees, which is the ideal bond angle for sp3 hybridized orbitals in a tetrahedral arrangement.
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you want to completely react to hydrochloric acid with magnesium ribbon in a chemistry experiment. How many grams of hydrochloric acid (HCI) are needed to completely react with 3.0 grams of magnesium (Mg)?
Answers
To completely react with 3.0 grams of magnesium (Mg), approximately 43.5 grams of hydrochloric acid (HCl) are needed.
The balanced chemical equation for the reaction between hydrochloric acid (HCl) and magnesium (Mg) is:
2HCl(aq) + Mg(s) → MgCl₂(aq) + H₂(g)
From the balanced equation, we can see that the molar ratio between HCl and Mg is 2:1. This means that for every 2 moles of HCl, 1 mole of Mg reacts.
First, we need to calculate the number of moles of Mg:
moles of Mg = mass of Mg / molar mass of Mg
moles of Mg = 3.0 g / 24.31 g/mol
moles of Mg ≈ 0.123 moles
According to the stoichiometry of the balanced equation, we can determine the number of moles of HCl required:
moles of HCl = 0.123 moles of Mg × 2 moles of HCl / 1 mole of Mg
moles of HCl = 0.246 moles
Finally, we can calculate the mass of HCl using its molar mass:
mass of HCl = moles of HCl × molar mass of HCl
mass of HCl = 0.246 moles × 36.46 g/mol
mass of HCl ≈ 8.97 grams
Therefore, approximately 8.97 grams of hydrochloric acid (HCl) are needed to completely react with 3.0 grams of magnesium (Mg).
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Ethanol (C₂H₆O) is combusted in air according to the following reaction:
C₂H₆O(l) + O₂(g) → CO₂(g) + H₂O(l)
How many grams of water would be produced by the complete combustion of 12.00 moles of ethanol in the presence of excess oxygen?
Answers
The amount of water that would be produced by the complete combustion of 12.00 moles of ethanol in the presence of excess oxygen in reaction C₂H₆O(l) + O₂(g) → CO₂(g) + H₂O(l) is 648.54 grams.
To determine how many grams of water would be produced by the complete combustion of 12.00 moles of ethanol (C₂H₆O) in the presence of excess oxygen, we need to first understand the balanced equation:
C₂H₆O(l) + O₂(g) → 2CO₂(g) + 3H₂O(l)
From the balanced equation, we can see that 1 mole of ethanol produces 3 moles of water. So, 12.00 moles of ethanol would produce:
12.00 moles of ethanol × (3 moles of H₂O / 1 mole of C₂H₆O)
= 36.00 moles of H₂O
Next, we need to convert moles of water to grams. The molar mass of water (H₂O) is 18.015 g/mol. So, 36.00 moles of water is equivalent to:
36.00 moles of H₂O × 18.015 g/mol
= 648.54 g
Therefore, the complete combustion of 12.00 moles of ethanol in the presence of excess oxygen would produce 648.54 grams of water.
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Sulfur dioxide, SO₂, is one gas produced when fossil fuels
are burned. When this gas reacts with water in the
atmosphere, an acid is produced forming acid rain. The pH
of the water in a lake changes when acid rain collects in the
lake. Two samples of the same rainwater are tested using
two indicators. Methyl orange is yellow in one sample of
this rainwater. Litmus is red in the other sample of this
rainwater.
Write the formula for one substance that can neutralize the
lake water affected by acid rain described.
Answers
The balanced chemical equation for this reaction is: NaHCO₃ + H⁺ → Na⁺ + CO₂ + H₂O
In order to neutralize the lake water affected by acid rain, a substance with a basic pH must be introduced. One such substance is sodium bicarbonate, NaHCO₃. When sodium bicarbonate reacts with acid, it produces carbon dioxide gas, water, and a salt. By adding sodium bicarbonate to the lake water affected by acid rain, the pH of the water can be raised and the harmful effects of the acid can be mitigated. This substance can be added in small amounts over time until the desired pH is reached.
Using a basic substance like sodium bicarbonate can help neutralize the harmful effects of acid rain on lake water.
One substance that can neutralize the lake water affected by acid rain is calcium carbonate (CaCO₃). When calcium carbonate reacts with the acidic solution produced by sulfur dioxide (SO₂) and water, it forms a neutral solution, preventing further harm to the lake ecosystem. This neutralization process helps to restore the pH balance of the water in the lake.
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Avogrados number was calculated by determining the number of atoms in
Answers
Avogadro's number, also known as Avogadro's constant, is approximately 6.022 x 10^23 particles per mole.
This constant was calculated by determining the number of atoms in a specific amount of a substance.
It is used to relate the amount of a substance in moles to the number of atoms or molecules it contains. The number was named after Italian scientist Amedeo Avogadro, who contributed significantly to the development of molecular theory and the mole concept.
Summary: Avogadro's number (6.022 x 10^23 particles per mole) was calculated by determining the number of atoms in a given amount of a substance, and it is used to convert between moles and the number of particles (atoms or molecules) in a substance.
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why is it important to use an appropriate instrument in measuring the distance of an object?
A.it gives precise and exact measurment
B.The measurements vary
C.Helps people process data accurately
D.Both A and C
nonsense:report
not nonsense:brainly and like
pls answer it properly
it is from science
Answers
It is important to use an appropriate instrument in measuring the distance of an object because it gives precise and exact measurements and also, it ensures that the measurement taken is accurate, consistent and reliable. (option A and C)
This is important because it helps people process data accurately. If measurements are not precise or exact, it can lead to errors in data analysis, research findings, and decision-making. Both A and C are correct as an appropriate instrument ensures that the data collected is precise, which leads to more accurate data analysis and decision-making. Hence, using an appropriate instrument is crucial to obtain accurate and reliable data. (options A and C)
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Which of the following science and engineering practice should occur first during typical scientific investigation
Answers
The following science and engineering practice should occur first during typical scientific investigation is "Asking Questions and Defining Problems."
This initial step is crucial because it sets the foundation for the entire investigation. By asking relevant questions and clearly defining the problems to be addressed, researchers can establish the scope, objectives, and direction for their investigation. In a scientific investigation, the process begins with curiosity and inquiry. Researchers observe phenomena, gather data, and identify patterns or inconsistencies that inspire questions. These questions should be specific, testable, and relevant to the field of study.
Once the questions have been formulated, the next step is to define the problems that the investigation aims to address. This involves identifying the knowledge gaps or inconsistencies in the existing understanding and determining how the investigation will contribute to filling these gaps or resolving these inconsistencies. In summary, asking questions and defining problems is the first and most critical practice in a typical scientific investigation. This step provides a solid foundation for the subsequent practices, including planning and carrying out investigations, analyzing and interpreting data, constructing explanations, and designing solutions.
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A student is constructing a cold pack using NaCl
(AHsoln =3.9 kJ/mol.) 35g of NaCl has been put into
pack. The temperature of the pack should not decline
more than 10 °C. The mass of the internal contents
(NaCl + water) should not exceed 70g. Can the cold
pack be constructed to meet these criteria? Support
your response with data from your calculations.
Answers
Based on calculations, it is possible to construct a cold pack using NaCl that meets the given criteria of not exceeding a temperature decline of 10°C and having a total internal contents mass of no more than 70g.
To determine if the cold pack can meet the criteria, we need to calculate the maximum temperature decline that can be achieved by dissolving 35g of NaCl in water. The formula for calculating the temperature change due to dissolution is:
ΔT = - (q / (m × c))
where ΔT is the temperature change, q is the heat released or absorbed during the dissolution process, m is the mass of the solution, and c is the specific heat capacity of the solution.
Since the dissolution of NaCl is exothermic, the value of q will be negative. The heat released can be calculated using the enthalpy of solution (AHsoln) of NaCl, which is given as 3.9 kJ/mol. The number of moles of NaCl dissolved can be calculated using its molar mass, which is 58.44 g/mol.
moles of NaCl = 35 g / 58.44 g/mol = 0.5997 mol
q = - (AHsoln × moles of NaCl) = - (3.9 kJ/mol × 0.5997 mol) = - 2.34 kJ
Next, we need to calculate the mass of water required to dissolve 35g of NaCl while maintaining a temperature decline of no more than 10°C. Assuming the initial temperature of the water is 20°C, the final temperature should not be lower than 10°C.
ΔT = -10°C
ΔT = - (q / (mwater × cwater))
mwatervater = q / (ΔT × cwater) = -2.34 kJ / (-10°C × 4.18 J/g°C) = 55.9 g
The total mass of the internal contents (NaCl + water) is 35g + 55.9g = 90.9g, which is higher than the specified limit of 70g. To meet the criteria, we need to reduce the amount of water used.
Let's assume we use the minimum amount of water required to dissolve 35g of NaCl while still maintaining a temperature decline of no more than 10°C. This would occur if all the heat released during the dissolution process was used to raise the temperature of the water to 30°C, instead of 20°C.
q = - (AHsoln × moles of NaCl) = - (3.9 kJ/mol × 0.5997 mol) = -2.34 kJ
ΔT = 10°C
ΔT = q / (mwater × cwater)
mwater = q / (ΔT × cwater) = -2.34 kJ / (10°C × 4.18 J/g°C) = 14.1 g
The total mass of the internal contents (NaCl + water) is now 35g + 14.1g = 49.1g, which is within the specified limit of 70g.
Therefore, we can conclude that it is possible to construct a cold pack using NaCl that meets the given criteria by dissolving 35g of NaCl in 14.1g of water.
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Express your answer using two significant figures
How many moles of gas must be forced into a 4.6 L tire to give it a gauge pressure of 33.2 psi at 26 ∘C ? The gauge pressure is relative to atmospheric pressure. Assume that atmospheric pressure is 14.7 psi so that the total pressure in the tire is 47.9 psi.
n = ______ mol
Answers
The solve this problem, we can use) n = number of moles of gas R = ideal gas constant (0.0821 L atm/mol K) T = temperature (in Kelvin) First, we need to convert the given temperature from Celsius to Kelvin and the pressure from psi to atmospheres.
Temperature in Kelvin T = 26°C + 273.15 = 299.15 K Pressure in atmospheres: 1 atm = 14.7 psi 47.9 psi * (1 atm / 14.7 psi) = 3.26 atm Now, we can plug the values into the Ideal Gas Law equation and solve for the number of moles (n). 3.26 atm * 4.6 L = n * 0.0821 L atm/mol K * 299.15 K Rearrange the equation to solve for n: n = (3.26 atm * 4.6 L) / (0.0821 L atm/mol K * 299.15 K) n ≈ 0.69 mol So, approximately 0.69 moles of gas must be forced into the tire to give it the desired pressure and temperature conditions.
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2.65 g KHP (molar mass=204.22 g/mol) was use to standardize a NaOH solution. the endpoint of titration was reached after 42.56 mL of NaOH was delivered. What is the molarity of the NaOH solution?
Answers
2.65 g KHP (molar mass=204.22 g/mol) was use to standardize a NaOH solution and the endpoint of titration was reached after 42.56 mL of NaOH was delivered. The molarity of the NaOH solution is 0.100 M.
To find the molarity of the NaOH solution, we need to use the balanced chemical equation for the reaction that occurred during the titration. This reaction is:
KHP + NaOH → NaKP + H2O
From the equation, we can see that 1 mole of NaOH reacts with 1 mole of KHP. Therefore, the number of moles of NaOH used in the titration can be calculated as:
moles NaOH = (42.56 mL)(1 L/1000 mL)(0.100 M) = 0.0004256 moles
Next, we can use the molar mass of KHP to calculate the number of moles of KHP used in the titration:
moles KHP = 2.65 g / 204.22 g/mol = 0.012979 moles
Since the reaction is a 1:1 stoichiometry, the number of moles of NaOH used is equal to the number of moles of KHP used. Therefore, we can set up an equation to find the molarity of the NaOH solution:
moles NaOH = moles KHP
0.0004256 moles = 0.012979 moles / x M
x = 0.100 M
Therefore, the molarity of the NaOH solution is 0.100 M.
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What mass of oxygen is required to completely react with 5 mol C8H18? I'M GIVING 20 POINTS FOR THIS QUESTION!
Answers
The mass of oxygen required to completely react with 5 mol of C8H18 is 640 g.
To find the mass of oxygen needed, first, we must determine the balanced equation for the reaction of C8H18 with oxygen.
The combustion reaction is:
C8H18 + 12.5 O2 → 8 CO2 + 9 H2O
From the balanced equation, we can see that 1 mol of C8H18 requires 12.5 mol of O2. So, for 5 mol of C8H18, we need:
5 mol C8H18 × (12.5 mol O2 / 1 mol C8H18) = 62.5 mol O2
Now, we convert moles of O2 to grams using the molar mass of O2 (32 g/mol):
62.5 mol O2 × (32 g O2 / 1 mol O2) = 640 g O2
To completely react with 5 mol of C8H18, 640 g of oxygen is required.
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5.
A student creates a solution of lithium chloride by dissolving 95.0 grams of LiCl in 2.24 L of water.
What will be the molarity of this new solution?
a) 1.00 M
b) 1.50 M
2.00 M
d) 2.50 M
Answers
The student created a solution of lithium chloride with a molarity of 1.00 M by dissolving 95.0 grams of LiCl in 2.24 L of water.
The molarity of the solution can be calculated using the formula:
Molarity (M) = moles of solute / volume of solution in liters
To find the moles of solute, we need to convert the given mass of LiCl into moles using its molar mass. The molar mass of LiCl is 42.39 g/mol.
95.0 g LiCl x (1 mol LiCl / 42.39 g LiCl) = 2.24 mol LiCl
Now, we can substitute the values into the molarity formula:
Molarity = 2.24 mol LiCl / 2.24 L = 1.00 M
Therefore, the answer is (a) 1.00 M. The student created a solution of lithium chloride with a molarity of 1.00 M by dissolving 95.0 grams of LiCl in 2.24 L of water.
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6 For each of the following uses, suggest whether you think a pure form of the
metal or an alloy would be better suited. Explain your answer in each case.
Answers
The choice between a pure form of the metal or an alloy depends on the specific use and requirements. Alloys often provide increased strength, durability, and resistance to environmental factors, while pure metals are typically used when electrical conductivity, malleability, or other properties are of utmost importance.
For each use, I will suggest whether a pure form of the metal or an alloy would be better suited.
1. Structural support in buildings - Alloy (e.g., steel)
Alloys like steel provide more strength and durability than pure metals. They are also resistant to corrosion and can handle a higher load.
2. Electrical wiring - Pure form (e.g., copper)
Pure metals like copper have higher electrical conductivity than alloys. This allows for more efficient transmission of electrical currents.
3. Aircraft components - Alloy (e.g., titanium alloy)
Alloys like titanium alloys are lightweight, strong, and resistant to high temperatures, which makes them ideal for aircraft components that need to endure extreme conditions.
4. Jewelry - Both pure form and alloy (e.g., gold and gold alloys)
Pure metals like gold are often used for jewelry because they are malleable, ductile, and aesthetically pleasing. However, alloys are also used to make jewelry more durable and less prone to damage, such as gold alloyed with copper or silver.
5. Kitchen utensils - Alloy (e.g., stainless steel)
Alloys like stainless steel are more resistant to corrosion and wear, making them more suitable for kitchen utensils that are exposed to moisture and high temperatures.
6. Battery components - Pure form (e.g., lithium)
Pure metals like lithium have high energy densities and are efficient in battery applications. The pure form of lithium allows for faster charging and discharging rates.
The choice between a pure form of the metal or an alloy depends on the specific use and requirements. Alloys often provide increased strength, durability, and resistance to environmental factors, while pure metals are typically used when electrical conductivity, malleability, or other properties are of utmost importance.
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1) Photon of certain type of electromagnetic radiation has a
wavelength of 47.2 Å. What is the frequency of this?
Answers
The frequency of electromagnetic radiation with a wavelength of 47.2 Å is 6.35 x [tex]10^18[/tex] Hz.
What is the difference between a covalent bond and an ionic bond?
To calculate the frequency of electromagnetic radiation, you can use the formula:
frequency = speed of light / wavelength
where the speed of light is a constant value of 299,792,458 meters per second.
First, you need to convert the given wavelength of 47.2 Å (angstroms) to meters. One angstrom is equal to 1 x [tex]10^-10[/tex] meters, so:
47.2 Å = 47.2 x [tex]10^-10[/tex] meters
Now, you can plug in the values into the formula:
frequency = 299,792,458 m/s / (47.2 x [tex]10^-10[/tex] m)
Simplifying the denominator:
frequency = 299,792,458 m/s / 0.0000000000472 m
frequency = 6.35 x [tex]10^18[/tex] Hz
Therefore, the frequency of the electromagnetic radiation with a wavelength of 47.2 Å is 6.35 x [tex]10^18[/tex] Hz.
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If all of the water in 430.0 mL of a .450 M KCI solution evaporates, what mass of KCI will remain?
Answers
When all the water in the 430.0 mL of 0.450 M KCl solution evaporates, approximately 14.42 g of KCl will remain.
To find the mass of KCl that will remain after the water evaporates, you can use the following steps:
1. Calculate the moles of KCl in the solution: Moles of solute = Molarity (M) × Volume (L)
Moles of KCl = 0.450 M × 0.430 L = 0.1935 moles
2. Find the molar mass of KCl: K (Potassium) = 39.098 g/mol, Cl (Chlorine) = 35.453 g/mol
Molar mass of KCl = 39.098 g/mol + 35.453 g/mol = 74.551 g/mol
3. Calculate the mass of KCl: Mass = Moles × Molar mass
Mass of KCl = 0.1935 moles × 74.551 g/mol = 14.42 g (approx.)
So, when all the water in the 430.0 mL of 0.450 M KCl solution evaporates, approximately 14.42 g of KCl will remain.
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Arrhenius Theory
Please help me understand this because, I don't get this
Answers
The Arrhenius theory is a model that explains how acids and bases react with each other. It was proposed by the Swedish chemist Svante Arrhenius in 1884.
According to the Arrhenius theory, an acid is a substance that donates a hydrogen ion (H+) in solution, and a base is a substance that accepts a hydrogen ion in solution. The theory also states that the rate of a chemical reaction is proportional to the concentration of the reacting substances. In other words, the faster the rate of a reaction, the higher the concentration of the reacting substances. The Arrhenius theory is often used to explain the relationship between temperature and the rate of chemical reactions.
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If 24.2 g of zinc is combined with hydrochloric acid (HCl) determine the concentration of the zinc chloride solution created if the total volume of solution was 150 mL.
Answers
Therefore, the concentration of the zinc chloride solution created is 4.93 M.
The balanced chemical equation for the reaction between zinc and hydrochloric acid is:
Zn + 2HCl → ZnCl2 + H2
The molar mass of zinc is 65.38 g/mol, so 24.2 g of zinc is:
24.2 g ÷ 65.38 g/mol = 0.370 mol Zn
According to the balanced chemical equation, 1 mol of Zn reacts with 2 mol of HCl to form 1 mol of ZnCl2. So, the number of moles of HCl required to react with 0.370 mol of Zn is:
0.370 mol Zn × 2 mol HCl/mol Zn = 0.740 mol HCl
The volume of the solution is given as 150 mL, which is 0.150 L. The concentration of HCl can be calculated as:
Concentration = Number of moles / Volume
Concentration = 0.740 mol / 0.150 L = 4.93 M
Therefore, the concentration of the zinc chloride solution created is 4.93 M.
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Exercise 19.70- Enhanced - with Feedback
MISSED THIS? Read Section
19.9 (Pages 878-881); Watch IWE 19.10.
Consider the evaporation of methanol at 25.0°C:
CH3OH (1)→ CH, OH (g).
▼ Part B
Ren
PCH,OH = 150.0mmHg
Express the free energy change in kilojoules to one decimal place.
15. ΑΣΦ
?
AG = 3.88
kJ
Submit
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This is the free energy change under standard conditions (AG), but you s
change under the given nonstandard conditions. The partial pressure of gase
the following equation to calculate free energy:
AG = AG + RT In Q
Answers
The free energy change for the evaporation of methanol at 25.0°C and a partial pressure of 150.0 mmHg is 3.9 kJ.
The free energy change (ΔG) can be calculated using the equation:
ΔG = ΔG° + RT ln(Q)
Where ΔG° is the standard free energy change, R is the gas constant, T is the temperature in Kelvin, and Q is the reaction quotient. In this case, the reaction is the evaporation of methanol, so the equation is:
CH₃OH (1) → CH₃OH (g)
The reaction quotient can be expressed as the partial pressure of the gaseous methanol product (PCH₃OH) divided by the standard state pressure (1 atm), since the other reactant is a pure liquid:
Q = PCH₃OH / 1 atm
Substituting the values into the equation, we get:
ΔG = ΔG° + RT ln(PCH₃OH / 1 atm)
Since the problem only gives us the partial pressure of CH₃OH (150.0 mmHg), we need to convert it to atm:
PCH₃OH = 150.0 mmHg / 760 mmHg/atm
PCH₃OH = 0.197 atm
Substituting the values into the equation, we get:
ΔG = ΔG° + (8.314 J/K/mol) x (298 K) x ln(0.197)
Converting the result to kJ and rounding to one decimal place, we get:
ΔG = 3.9 kJ
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The reaction N2 + 3 H2 → 2 NH3 is used to produce ammonia. When 450. g of
hydrogen was reacted with nitrogen, 1575 g of ammonia were produced. What is the
percent yield of this reaction?
A) 62.1%
B) 41.5%
C) 30.8%
D) 20.7%
Answers
The percent yield of this reaction is 62.1%.
To calculate the percent yield, we need to first find the theoretical yield of ammonia.
1. Convert the mass of hydrogen (H2) to moles using its molar mass (2 g/mol):
450 g H2 * (1 mol H2 / 2 g H2) = 225 mol H2
2. Use the stoichiometry of the balanced equation to find the moles of ammonia (NH3) produced:
225 mol H2 * (2 mol NH3 / 3 mol H2) = 150 mol NH3
3. Convert the moles of ammonia to grams using its molar mass (17 g/mol):
150 mol NH3 * (17 g NH3 / 1 mol NH3) = 2550 g NH3 (theoretical yield)
4. Calculate the percent yield using the given actual yield (1575 g) and the theoretical yield (2550 g):
Percent yield = (actual yield / theoretical yield) * 100
Percent yield = (1575 g / 2550 g) * 100 = 61.76% ≈ 62.1%
The percent yield of ammonia in this reaction is approximately 62.1%.
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You need to prepare 100 mL of a 0.050 M solution of calcium chloride (CaCl2).
Answers
0.5549 g is the Molar mass of calcium chloride CaCl₂ that is needed to form a 100.0 ml solution of 0.150 m CaCl₂.
To prepare 100 mL of a 0.050 M solution of calcium chloride (CaCl₂), you will need to follow these steps:
1. Determine the amount of CaCl₂ needed: Use the formula n = M × V, where n is the amount of substance in moles, M is the molarity, and V is the volume in liters. In this case, n = 0.050 M × 0.100 L = 0.005 moles.
2. Calculate the mass of CaCl₂: Multiply the moles (n) by the molar mass of CaCl₂ (110.98 g/mol). Mass = 0.005 moles × 110.98 g/mol = 0.5549 g.
Everybody wants to know how many molecules are there in a certain substance. Both in terms of mass and size, atoms and molecules are exceedingly tiny. The molar mass is the mass of one sample mole. Connect the atomic masses (atomic weights) of all the atoms in the molecule to obtain the molar mass. Calculate each element's atomic mass using the mass specified in the Periodic Table or Atomic Weight Table.
3. Measure and dissolve the CaCl₂: Weigh out 0.5549 g of calcium chloride and dissolve it in a small amount of distilled water.
4. Dilute to the desired volume : Mix well to ensure a uniform concentration
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The Complete question is
Calculate the mass of calcium chloride CaCl₂ that is needed to form a 100.0 ml solution of 0.150 m CaCl₂?
Compound X has a relative molecular mass of 58 Deduce the molecular formula of compound X.
Answers
The deduction of the molecular formula of compound X that has a relative molecular mass of 58 is C₂H₄.
To deduce the molecular formula of compound X, we need to know the empirical formula and the relative molecular mass. The empirical formula gives the simplest whole-number ratio of atoms in a compound, while the molecular formula gives the actual number of atoms of each element in a molecule.
Assuming the empirical formula of compound X is CH₂ (which gives a relative molecular mass of 14 + 2 × 12 = 38), we can calculate the molecular formula as follows:
Molecular formula = Empirical formula × n, where n = relative molecular mass / empirical formula mass
n = 58 / 38 = 1.53
Therefore, the molecular formula of compound X is approximately C1.53H3.06, which we can round up to C₂H₄. So, the molecular formula of compound X is C₂H₄.
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